If a 25 kg box is pushed 10 m with a net force of 30 N, what is the work done on the box?

To determine the work done on the box, we use the formula for work, which is the product of the net force applied to an object and the distance over which that force is applied. The equation is given by:

[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) ]

In this scenario, since the force is applied in the same direction as the displacement of the box, the angle ( \theta ) is 0 degrees. The cosine of 0 degrees is 1, so the equation simplifies to:

[ \text{Work} = \text{Force} \times \text{Distance} ]

Plugging in the values:

• Net force = 30 N

• Distance = 10 m

Calculating the work done:

[ \text{Work} = 30 , \text{N} \times 10 , \text{m} = 300 , \text{J} ]

Thus, the work done on the box is 300 joules. This demonstrates a key principle that work is directly influenced by the amount of force applied and the distance over which that force is exerted. The correct